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Choose a method from fingerprints

Chapter 3 - Recognition before execution

Solving is not only performing a method. It is deciding which method fits. Homework grouped by method hides that decision because every exercise under "Separable Equations" is separable. Real problems do not carry those labels.

This chapter builds a method-selection guide you will retrieve and refine throughout the book.

Normalize, then inspect

Before naming a method:

  1. identify the unknown function and independent variable;
  2. identify the highest derivative and therefore the order;
  3. move or divide terms to expose a familiar form; and
  4. check whether a simpler qualitative answer should come first.

The same equation can wear a disguise. For example,

(1+t)y′=2y (1+t)y'=2y

looks different from y′=a(t)b(y)y'=a(t)b(y) until division gives

y′=21+ty. y'=\frac{2}{1+t}y.

Now its separable fingerprint is visible. It is also linear; either method works.

The first-course method map

Autonomousy' = f(y)

First draw the phase line: a state axis with arrows showing motion. Equilibria and their response to nearby starting states may answer the important question without a formula.

Separabley' = a(t)b(y)

Move all state factors beside dydy and all time factors beside dtdt.

First-order lineary' + p(t)y = q(t)

Use an integrating factor, a multiplier that creates one product derivative.

Second-order constant coefficientay'' + by' + cy = g(t)

Use characteristic roots, the rates of the equation's exponential solutions, for natural motion; add a response shaped like the input.

Linear systemx' = Ax

Read eigen-directions and eigenvalues, which encode basic motions such as growth, decay, and oscillation. Then connect them to a phase portrait: a picture of paths through state space.

No elementary fingerprinty' = f(t,y)

Use a field, numerical approximation, bounds, or a qualitative argument.

These categories overlap. y′=tyy'=ty is autonomous? No, because the rate contains tt. It is both separable and linear. Choose the shorter route and retain the other as a check.

Lab: classify before solving

Method trainerEight mixed equations; no chapter labels.

Contrast cases: train the boundary

Deep recognition grows when similar-looking examples require different moves.

Separable

y′=t(1+y)y'=t(1+y)

dy1+y=t dt\dfrac{dy}{1+y}=t\,dt

Why

one factor uses only tt, the other only yy

Linear, not separable

y′=t+yy'=t+y

y′−y=ty'-y=t

Why

the sum t+yt+y cannot split into a(t)b(y)a(t)b(y)

Neither elementary form

y′=t+y2y'=t+y^2

use a field or numerical method

Why

nonlinear in yy, and no product separates

Almost separable. Which equation fails the separable test?

Worked example: name two routes

Classify ty′+2y=t3ty'+2y=t^3, t>0t\gt 0method selection
  1. Normalize. Divide by tt: y′+(2/t)y=t2y'+(2/t)y=t^2.
  2. Test separability. Rewriting gives y′=t2−(2/t)yy'=t^2-(2/t)y, a sum whose terms mix tt and yy. It does not split into a(t)b(y)a(t)b(y).
  3. Test linearity. It matches y′+p(t)y=q(t)y'+p(t)y=q(t) with p(t)=2/tp(t)=2/t and q(t)=t2q(t)=t^2.
  4. State the next move. Use the integrating factor μ=e∫2/t dt=t2\mu=e^{\int 2/t\,dt}=t^2 on t>0t\gt 0. Chapter 5 develops the method.

Fade the classification

Classify each equation and state only the first move, not the full solution.

  1. y′=(t2+1)e−yy'=(t^2+1)e^{-y}
  2. y′−1ty=ty'-\frac{1}{t}y=t
  3. y′=y2−4y'=y^2-4
  4. y′′−5y′+6y=0y''-5y'+6y=0
Check the fingerprints
  1. Separable; multiply by eye^y and pair eydye^y dy with (t2+1)dt(t^2+1)dt.
  2. First-order linear; compute an integrating factor on an interval excluding zero.
  3. Autonomous and separable; first find equilibria y=±2y=\pm2 and draw a phase line.
  4. Homogeneous second-order constant coefficient; form r2−5r+6=0r^2-5r+6=0.

Method choice is a claim you can test

Before executing, point to the exact fingerprint. "It looks linear" is too vague. Say "after dividing by tt, the equation has y′+p(t)y=q(t)y'+p(t)y=q(t), and yy appears only to the first power."

Error clinic: distributing dydy as if it were an algebra tile

Separation is justified through differential or integral notation, but only after the rate factors correctly. From y′=t+yy'=t+y, writing dy/y=t dt+dtdy/y=t\,dt+dt does not separate anything: the right side still came from an invalid division of a sum.

Practice

For every problem, write a one-line fingerprint justification before any algebra.

  1. Practice - classification

    3.1 Classify: (a) y′=t2/yy'=t^2/y, (b) y′+ety=1y'+e^t y=1, (c) y′=ysin⁡yy'=y\sin y, (d) y′′+9y=0y''+9y=0.

    Detailed solution

  2. Practice - contrast

    3.2 Explain why y′=ty+ty'=t y+t is separable, while y′=ty+1y'=t y+1 is generally not. Identify a method that works for both.

    Detailed solution

  3. Integrated - multiple routes

    3.3 Find every applicable early-course method for y′=y/ty'=y/t, t>0t\gt 0. Which route uses less machinery?

    Detailed solution

  4. Challenge - strategy boundary

    3.4 For y′=y2+ty'=y^2+t, explain precisely why the separable and first-order linear fingerprints fail. List three useful things you can still do without an elementary formula.

    Detailed solution

  5. Practice - extension

    3.5 Normalize (t−2)y′+3y=(t−2)2(t-2)y'+3y=(t-2)^2. Identify the method and coefficient functions on intervals avoiding 2. Which interval containing t=3t=3 is appropriate for the normalized equation? What condition would the original equation impose if a differentiable solution extended to t=2t=2? Do not solve.

    Detailed solution

  6. Challenge - transfer

    3.6 The equation y′=y+ty2y'=y+ty^2 is neither first-order linear nor separable in its given variables. Record the equilibrium lost by dividing by yy, then set v=1/yv=1/y on a nonzero branch. Derive the equation for vv and identify its method. Explain why the transformed equation does not make the original equation linear in yy.

    Detailed solution

Retrieve the map

On blank paper, recreate the six-box method map from memory. For each box, write a representative equation that did not appear on this page. Then compare.

Next: Turn the separable fingerprint into a reliable sequence of moves.